# My Awcgs Blogs

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Here is a triangle, such as △ABC,∠ B as supporting an object's former vertices,

Its weight is:Gn,objects behind the fulcrum weight is: Gm,Is the total weight: Ge,As shown in figure.

The graph of the symbol definition is:d=AC,AB=c,AC=b,BC=a,AL=x,OL=y,

tanθ=BC/AC=a/b,Cosθ=AC/AB=b/a.

The problems need to be solved as follows:

1.When the object's centerline is horizontal reference line (green line) above,also is h1＞h2,θis positive angle(that is ＋3°、＋5°、＋7°、＋10°,etc),at this time B Angle (B point) is rising,so that the object front-end(B point) rising status.

2.1.When the object's centerline is horizontal reference line (green line) below,also is

h1＜h2,θis negative angle,(that is -3°、-5°、-7°、-10°,etc),at this time B Angle (B point) is to drop,so that the object front-end(B point) declining state.

⑴ I write the formula is:Ge*(x－y*tanθ)*cosθ＝Gn*b,but I don't know whether it is right, please revise and work out y,

⑵ Calculate + 3°、+ 5°、+ 7°、+ 10°and - 3°、- 5°、- 10 °to correspond a (BC) in length.